Direct current
η = (P / (I * U)) * %
Alternating single-phase
η = (P / (I * U₀ * cosφ)) * %
Alternating two-phase
η = (P / (I * U * cosφ)) * %
Alternating three-phase
η = (P / (√3 * I * U * cosφ)) * %
Where:
η = Efficiency(%)
P = Power (W)
U₀ = Voltage [L - N] (V)
U = Voltage [L - L](V)
I = Current(A)
cosφ = Power factor
Use this tool to see how efficiently your motor is running. Enter voltage, current, power factor, and output to check if it’s wasting energy or needs replacement.
Motor nameplates list rated efficiency under ideal full-load conditions—but in the field, voltage imbalance, partial load, or aging can significantly reduce real-world performance. This tool uses your actual voltage (V), current (I), power factor (PF), and shaft output power to estimate true motor efficiency and flag anomalies.
Enter measured parameters to automatically calculate:
Electrical Input Power (kW) – total power drawn from the supply
Motor Efficiency (%) – ratio of mechanical output to electrical input
Validity Check – alerts if efficiency >100% (indicating measurement error)
Supports single-phase, two-phase, and three-phase AC systems with real-time bidirectional calculation (you can also solve for unknown output power).
Electrical Input Power (P in):
• Single-phase: P in = V × I × PF
• Two-phase: P in = V × I × PF
• Three-phase: P in = √3 × V × I × PF
Efficiency (η): η = (P out / P in) × 100%
Example 1: Healthy three-phase pump motor
Measured: 400 V, 10 A, PF = 0.85, Shaft Output = 5.5 kW
→ P in = √3 × 400 × 10 × 0.85 ≈ 5.95 kW
→ Efficiency = (5.5 / 5.95) × 100% ≈ 92.4%
Insight: Matches typical IE3 performance at ~75% load.
Example 2: Invalid measurement (common pitfall)
Measured: 230 V, 5 A, PF = 0.8, Shaft Output = 1.1 kW
→ P in = 230 × 5 × 0.8 = 0.92 kW
→ Efficiency = (1.1 / 0.92) × 100% ≈ 119.6% ❌
Diagnosis: Efficiency >100% is physically impossible. Likely causes:
– Output power overestimated (e.g., using HP without derating)
– Current or PF measured incorrectly
– Motor not at steady state
Efficiency cannot exceed 100% — values above indicate input error
Use true RMS power analyzers for accurate V, I, and PF readings
Always measure under stable, steady-state operating conditions
Compare your result to IE-class benchmarks:
IE1: ~70–85%
IE2: ~85–90%
IE3: ~90–96%
Low efficiency may signal bearing wear, voltage imbalance, or undersized loading
Not accurately. While some tools estimate output from nameplate data, true efficiency requires measured mechanical output (via torque sensor or calibrated load test). This calculator assumes you have that value.
IE3 (Premium Efficiency) motors typically operate 2–5% more efficiently than IE2 (High Efficiency) models. For a 10 kW motor running 4,000 hours/year, that gap can save 800–2,000 kWh annually.
Motors are most efficient near full load (75–100%). At 50% load, efficiency can drop by 5–15%. Running a large motor at low load often wastes more energy than using a smaller, properly sized unit.
This always indicates a measurement error. Common issues include using mechanical horsepower without converting correctly (1 HP = 0.746 kW), misreading current on a clamp meter, or measuring during startup transients.